LeetCode 165: Compare Version Numbers

Compare two version numbers version1 and version1.
If version1 > version2 return 1, if version1 < version2 return -1, otherwise return 0.
You may assume that the version strings are non-empty and contain only digits and the . character.
The . character does not represent a decimal point and is used to separate number sequences.
For instance, 2.5 is not "two and a half" or "half way to version three", it is the fifth second-level revision of the second first-level revision.
Here is an example of version numbers ordering:

0.1 < 1.1 < 1.2 < 13.37

public class Solution {
    public int compareVersion(String version1, String version2) {
        // Note: Many special cases, e.g., "1" vs. "1.0.25"
        String[] v1 = version1.split("\\.");
        String[] v2 = version2.split("\\.");
        
        int n1 = v1.length;
        int n2 = v2.length;
        
        int ver1, ver2;
        
        for (int i = 0; i < Math.max(n1, n2); i++)
        {
            if (i < n1)
                ver1 = Integer.valueOf(v1[i]);
            else
                ver1 = 0;
                
            if (i < n2)
                ver2 = Integer.valueOf(v2[i]);
            else
                ver2 = 0;
                
            if (ver1 > ver2)
                return 1;
            else if (ver1 < ver2)
                return -1;
        }
        
        return 0;
    }
}