For example,
Given
[1,2,0]
return 3
,and
[3,4,-1,1]
return 2
.
Your algorithm should run in O(n) time and uses constant space.
public class Solution { public int firstMissingPositive(int[] A) { // Put the element, which value is i, in position i – 1. // After finishing doing this, go through the array to find the first missing positive integer. int n = A.length; int i = 0; while (i < n) { if (A[i]>=1 && A[i]<=n && A[i]!=i+1 && A[A[i]-1]!=A[i]) swap(A, i, A[i]-1); else i++; } for (i = 0; i < n; i++) if (A[i] != i+1) return i+1; return n+1; } private void swap(int[] A, int i, int j) { int tmp = A[i]; A[i] = A[j]; A[j] = tmp; } }
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